您好贾斯汀，我认为如果您触发波长扫描，〜30ms延迟可能是正常的。
最小扫描时间似乎约为75ms，即使是非常短的范围，因此这可能是机械光栅运动的加速时间所决定的。
您可以通过将跨度设置为零来检查，中心波长设置在您想要的位置。
然后“扫描”将显示信号在恒定波长下的时间依赖性，并且不会产生机械延迟。
当然，如果这是你的目标，这并不能很容易地为你提供频谱。
然后在触发后使用延迟可能是您最好的方法。
麦克风
以上来自于谷歌翻译
以下为原文
Hello Justin,
I think the ~30ms delay may be normal if you are triggering a wavelength sweep. The minimum sweep time seems to be about 75ms, even for very short ranges, so this is probably dominated by acceleration times for the mechanical grating movements.
You could check that by setting the span to zero, with the center wavelength set where you want it. Then the "sweep" will show the time dependence of the signal at constant wavelength and won't have the mechanical delay. Of course that doesn't give you the spectrum very easily if that is your goal. Then using the delay after the trigger is probably your best approach.
Mike
您好贾斯汀，我认为如果您触发波长扫描，〜30ms延迟可能是正常的。
最小扫描时间似乎约为75ms，即使是非常短的范围，因此这可能是机械光栅运动的加速时间所决定的。
您可以通过将跨度设置为零来检查，中心波长设置在您想要的位置。
然后“扫描”将显示信号在恒定波长下的时间依赖性，并且不会产生机械延迟。
当然，如果这是你的目标，这并不能很容易地为你提供频谱。
然后在触发后使用延迟可能是您最好的方法。
麦克风
以上来自于谷歌翻译
以下为原文
Hello Justin,
I think the ~30ms delay may be normal if you are triggering a wavelength sweep. The minimum sweep time seems to be about 75ms, even for very short ranges, so this is probably dominated by acceleration times for the mechanical grating movements.
You could check that by setting the span to zero, with the center wavelength set where you want it. Then the "sweep" will show the time dependence of the signal at constant wavelength and won't have the mechanical delay. Of course that doesn't give you the spectrum very easily if that is your goal. Then using the delay after the trigger is probably your best approach.
Mike
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