您好我对ST的FOC SDK解决方案有疑问。
ST提供工作台工具,称为“ST电机控制工作台”,用于BLDC电机控制应用。
用户可以配置功率级设置等。
在工作台工具的“功率级”部分,我可以选择如何测量电机相位的电流,如3sh,1sh,2ICS。
如果我选择“两个绝缘电流传感器”,则只有一个选项。这是ICS的收益。
这是否意味着“每1A的隔离运算放大器的第二电压输出”?
ex)分流电阻:30m欧姆
额定电动机相电流:1A
隔离运算放大器的第一电压输出(运算放大器的输入电压):30mV
理想运算放大器增益:8
isolted运算放大器的第二电压输出(运算放大器的输出电压):240mV
因此,ICS增益为0.240V / A.
这是对的吗?
我多次查看了FOC SDK用户手册,但我没有找到。
所以,请通知我。谢谢。
#ics#foc-sdk
以上来自于谷歌翻译
以下为原文
Hi I have some ques
tion about FOC SDK solution of ST.
ST provides workbench tool which is called 'ST Motor Control Workbench' for BLDC motor control application.
User is able to config power stage setting and etc.
In 'Power Stage' section of workbench tool, I can choose how I measure the current of motor phase such as 3sh, 1sh, 2ICS.
If I choose 'Two insulated current sensor', there is only one option. it is ICS gain.
Is it means that '2nd voltage output of Isolated opamp per 1A'?
ex) shunt resistor : 30m ohm
nominal motor phase current : 1A
1st voltage output of isolated opamp(input voltage of opamp) : 30mV
Ideal opamp gain : 8
2nd voltage output of isolted opamp(output voltage of opamp): 240mV
Thus, ICS gain is 0.240V/A
Is it correct?
I reviewed FOC SDK user manual many times, but I didn't find that.
So, please inform to me about that. Thanks.
#ics #foc-sdk