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王磊

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[问答]

怎么通过L298N驱动Peltier元件

嗨,


我想驱动珀耳帖元件来控制一个模块的温度。 Peltier规格如下:
Imax = 9A,Vmax = 3.75V。

这种4个珀耳帖串联连接以控制模块温度。

我打算用L298N来驱动它。如图所示,如果我将两个引脚串联连接L298N,那么我将能够驱动高达4A的电流。但是,为了控制我的模块温度,Peltier正在下沉平均4A电流。
所以,我不能使用单个L298N IC,因为它会加热过多而且会损坏。

所以,我想知道是否可以并联使用两个L298N IC来提供更高的电流。
如果是这样,请建议我输入和输出引脚连接。

谢谢&问候,
Sachin Panchal

以上来自于谷歌翻译


以下为原文






Hi,


I want to drive peltier element to control temperature of one module. Peltier specifications are:
Imax = 9A and Vmax = 3.75V.

Such 4 peltiers are connected in series to control to module temperature.

I am planning to use L298N for driving it. As shown if I connect L298N two pins in series then I will be able to drive current upto 4A. But, to control my module temperature, Peltier is sinking average 4A current.
So, It I can't use single L298N IC as it will heat too much and also it will damage.

So, I want to know whether it is possible to use two L298N ICs in parallel to give higher current.
If so then please advice me for input and output pin connections.

Thanks & Regards,
Sachin Panchal

回帖(1)

刘璐

2018-11-29 10:39:49
你好,
 
 
 并联更多L298N并不是因为双极技术的特性而被推荐。饱和电压的长度及其随温度的变化可能导致其中一个器件驱动的电流明显高于另一个器件。
 此外,两个并联的L298N仅可驱动高达8 A(实际最大负载电流可能受功耗限制)。
 
 我建议并行使用三个L6203。
 
 问候
 恩里科

以上来自于谷歌翻译


以下为原文





Hello,


Paralleling more L298N is not reccomended because the bipolar technology characteristics. The spead of the saturation voltage and its variation with the temperature could cause one of the devices driving a current which is significantly higher than the other one.
Moreover two L298N in parallel can drive up to 8 A only (the actual maximum load current is probably limited by the power dissipation).

I suggest to use three L6203 in parallel.

Regards
Enrico
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