venky228写道:
大家好,
我对vhdl coading(原文如此)非常新,我需要在altium nano board 3000上做项目,它使用了斯巴达3an。
它包含ADC084SO21和DAC084S085。
现在我有了ADC_DAC接口的代码,即如果我给ADC模拟信号,我通过DAC获得相同的信号。
现在对于相同的输入信号,我希望通过DAC输出信号的幅度是输入幅度的两倍(即如果我在adc中给出1v信号,我必须通过dac获得2v)。
现在我想知道我应该在vhdl coading(sic)中做些什么来增加相同输入的输出。
提前致谢
ÿ
将是开始的地方。
实施细节留给读者练习。
----------------------------是的,我这样做是为了谋生。
以上来自于谷歌翻译
以下为原文
venky228 wrote:
Hello to every one,
im very new to vhdl coading (sic) and i need to do project on altium nano board 3000, which uses spartan 3an. it contains ADC084SO21 and DAC084S085. Now im having the code for ADC_DAC Interfacing, ie if i give analog signal to ADC im getting the same signal through DAC. Now for the same input signal i want the amplitude of output signal through DAC as twice the amplitude of input(ie if i give 1v signal in adc , i have to get 2v through dac ). Now i want to know what should i do in the vhdl coading (sic) inorder to increase the output for same input.
thanks in advance
y <= x * 2;
would be the place to start.
The implementation details are left as an exercise for the reader.
----------------------------Yes, I do this for a living.
venky228写道:
大家好,
我对vhdl coading(原文如此)非常新,我需要在altium nano board 3000上做项目,它使用了斯巴达3an。
它包含ADC084SO21和DAC084S085。
现在我有了ADC_DAC接口的代码,即如果我给ADC模拟信号,我通过DAC获得相同的信号。
现在对于相同的输入信号,我希望通过DAC输出信号的幅度是输入幅度的两倍(即如果我在adc中给出1v信号,我必须通过dac获得2v)。
现在我想知道我应该在vhdl coading(sic)中做些什么来增加相同输入的输出。
提前致谢
ÿ
将是开始的地方。
实施细节留给读者练习。
----------------------------是的,我这样做是为了谋生。
以上来自于谷歌翻译
以下为原文
venky228 wrote:
Hello to every one,
im very new to vhdl coading (sic) and i need to do project on altium nano board 3000, which uses spartan 3an. it contains ADC084SO21 and DAC084S085. Now im having the code for ADC_DAC Interfacing, ie if i give analog signal to ADC im getting the same signal through DAC. Now for the same input signal i want the amplitude of output signal through DAC as twice the amplitude of input(ie if i give 1v signal in adc , i have to get 2v through dac ). Now i want to know what should i do in the vhdl coading (sic) inorder to increase the output for same input.
thanks in advance
y <= x * 2;
would be the place to start.
The implementation details are left as an exercise for the reader.
----------------------------Yes, I do this for a living.
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