如何在不降低帧率的情况下最小化时间？

你好，
你用什么API做这个阅读？
XFEDATA还是Begindataxfer /WaITFrxFEF/FixDATAXFER的异步方法？
当做，
阿南德



     以下为原文
  Hi,
    What APIs are you using to do this read?
    Xferdata or the async method of Begindataxfer/waitforxfer/finishdataxfer?
    Regards,
    Anand

你好，阿南，
XFelDATA（）函数。
当做，
以色列



     以下为原文
  Hello Anan,
    XferData() function.
    Regards,
    Israel

我想知道是否可以在同一时间开始多个总线交易（根据UB3.0规范第8.1章，它不是）。
它是，具有2个DMA通道自动从GPIF到批量端点的一对一。GPIF向端点发送一个单独的帧（如需要的缓冲区一样多），并在与另一个端点执行相同的操作之后，等等。同时，PC将在2个不同的线程中等待这两个事务。
这样，当一个事务完成时，PC中的另一个线程就准备好接收数据，因为先前正在等待，并且请求之间的时间被移除。
无论如何，我不确定是否可以如上所述。
最好的问候，
以色列



     以下为原文
   I was wondering If could be possible to begin more than one IN bus transaction at the same time (according to USB3.0 spec chapter 8.1 it isn't). 
    It is, having 2 DMA channels auto one-to-one from GPIF to an IN BULK endpoint. GPIF sends a single frame (as many buffers as required) to an endpoint and after do the same to the other endpoint and so on. Meanwhile, the PC will waiting both transactions in 2 different threads.
    This way when one transaction finishes, the other thread in the PC is ready to receive data because was waiting previously and the time between requests is removed.
    Anyway, I am not sure if it can be done as indicated above.
    Best regards,
    Israel

如果使用XFelDATA（），它就是这样工作的。一旦传输完成，它将返回，然后你将排队的下一个转移，有浪费时间从传输完成时，下一个排队。在你的情况下，这就是造成2～5ms延迟的原因。
BeaDimaTaxFr/WaiFracxFr/FixDATAXFER允许您排队多路传输。这样一来，只要一个传输完成，下一个就排队了。所以转移率会更快。请使用SuraMal/Turror作为例子来理解如何使用异步方法。
当做，
阿南德



     以下为原文
  If you use Xferdata() this is how it works. Once the transfer complete it will return and then you'll queue up the next transfer and there is time wasted from the time a transfer completes and the next one is queued. In your case this is what is causing the 2~5ms delay.
    Begindataxfer/waitforxfer/finishdataxfer lets you queue mulitple transfer. This way as soon as one transfer completes the next one is queued. So the transfer rate will be faster. Please use screamer/streamer as example to understand how to use the async method
    Regards,
    Anand

谢谢你，阿南德，
你让我走上了正确的方向。现在它正在工作。
我还有疑问。我正在与重叠数组大小斗争，因为我将大小设置为CySist.ReopApple AlalLosiScess。最后使用20作为流应用程序。那20意味着什么？.
最好的问候，
以色列



     以下为原文
   Thank you Anand,
    You put me on the right direction. Now it is working.
    I have a doubt yet. I was struggling with overlapped array size because I set size to CyConst.OverlapSignalAllocSize. Finally it worked using 20 as in stream application. What does that 20 mean?.
    Best regards,
    Israel